HackerRank - Java Regex

Write a class called MyRegex which will contain a string pattern. You need to write a regular expression and assign it to the pattern such that it can be used to validate an IP address. 

Use the following definition of an IP address:

IP address is a string in the form "A.B.C.D", where the value of A, B, C, and D may range from 0 to 255. Leading zeros are allowed. The length of A, B, C, or D can't be greater than 3.

Some valid IP address:

000.12.12.034

121.234.12.12

23.45.12.56

Some invalid IP address:

000.12.234.23.23

666.666.23.23

.213.123.23.32

23.45.22.32.

I.Am.not.an.ip

Sample Input

000.12.12.034

121.234.12.12

23.45.12.56

00.12.123.123123.123

122.23

Hello.IP

Sample Output

true

true

true

false

false

false

Java Code:

import java.util.Scanner;

public class javaRegex {

    public static void main(String[] args)

    {

        Scanner in = new Scanner(System.in);

        while(in.hasNext())

        {

            String IP = in.next();

            System.out.println(IP.matches(new MyRegex().pattern));

        }

        in.close();

    }

}

class MyRegex

{

    String pattern="^((25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\\\\.){3}(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)$";

}